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Display all possible state transitions in a bug if the user is not

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logged in.  Since they haven't logged in, we don't know what they will
be allowed to do.  And users who disable cookies tend to pretty often
not be logged in.


git-svn-id: svn://10.0.0.236/trunk@61203 18797224-902f-48f8-a5cc-f745e15eee43
This commit is contained in:
terry%mozilla.org
2000-02-17 15:53:40 +00:00
parent e852b90ee9
commit 567c73317f
2 changed files with 14 additions and 4 deletions
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15
mozilla/webtools/bugzilla/bug_form.pl
View File

@@ -460,11 +460,18 @@ my $knum = 1;
my $status = $bug{'bug_status'};
my $canedit = UserInGroup("editbugs");
# In the below, if the person hasn't logged in ($::userid == 0), then
# we treat them as if they can do anything. That's because we don't
# know why they haven't logged in; it may just be because they don't
# use cookies. Display everything as if they have all the permissions
# in the world; their permissions will get checked when they log in
# and actually try to make the change.
my $canedit = UserInGroup("editbugs") || ($::userid == 0);
my $canconfirm;
if ($status eq $::unconfirmedstate) {
$canconfirm = UserInGroup("canconfirm");
$canconfirm = UserInGroup("canconfirm") || ($::userid == 0);
if ($canedit || $canconfirm) {
print "<INPUT TYPE=radio NAME=knob VALUE=confirm>";
print "Confirm bug (change status to <b>NEW</b>)<br>";
@@ -473,8 +480,8 @@ if ($status eq $::unconfirmedstate) {
}
if ($::userid && ($canedit || $::userid == $assignedtoid ||
$::userid == $reporterid || $::userid == $qacontactid)) {
if ($canedit || $::userid == $assignedtoid ||
$::userid == $reporterid || $::userid == $qacontactid) {
if (IsOpenedState($status)) {
if ($status ne "ASSIGNED") {
print "<INPUT TYPE=radio NAME=knob VALUE=accept>";

3
mozilla/webtools/bugzilla/process_bug.cgi
View File

@@ -279,6 +279,9 @@ sub ChangeStatus {
} else {
$::query .= "bug_status = '$str'";
}
$::FORM{'bug_status'} = $str; # Used later for call to
# CheckCanChangeField to make sure this
# is really kosher.
}
}