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Checking in khanson's patch for bug 85112, based on joemansh@interl.net's algorithm (r=beard, sr=me).

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git-svn-id: svn://10.0.0.236/trunk@101635 18797224-902f-48f8-a5cc-f745e15eee43
This commit is contained in:
brendan%mozilla.org 2001-08-22 05:42:16 +00:00
parent d8e621de9c
commit 5bd9bfb18a
1 changed files with 8 additions and 30 deletions
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38
mozilla/js/src/jsdate.c
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@ -190,38 +190,16 @@ TimeWithinDay(jsdouble t)
static jsint
YearFromTime(jsdouble t)
{
jsint lo = (jsint) floor((t / msPerDay) / 366) + 1970;
jsint hi = (jsint) floor((t / msPerDay) / 365) + 1970;
jsint mid;
jsint y = (jsint) floor(t /(msPerDay*365.2425)) + 1970;
jsdouble t2 = (jsdouble) TimeFromYear(y);
/* above doesn't work for negative dates... */
if (hi < lo) {
jsint temp = lo;
lo = hi;
hi = temp;
if (t2 > t) {
y--;
} else {
if (t2 + msPerDay * DaysInYear(y) <= t)
y++;
}
/* Use a simple binary search algorithm to find the right
year. This seems like brute force... but the computation
of hi and lo years above lands within one year of the
correct answer for years within a thousand years of
1970; the loop below only requires six iterations
for year 270000. */
while (hi > lo) {
mid = (hi + lo) / 2;
if (TimeFromYear(mid) > t) {
hi = mid - 1;
} else {
if (TimeFromYear(mid) <= t) {
jsint temp = mid + 1;
if (TimeFromYear(temp) > t) {
return mid;
}
lo = mid + 1;
}
}
}
return lo;
return y;
}
#define InLeapYear(t) (JSBool) (DaysInYear(YearFromTime(t)) == 366)