Changed implementation of toString(<base>) to use Waldemar's code from
SpiderMonkey. git-svn-id: svn://10.0.0.236/trunk@60249 18797224-902f-48f8-a5cc-f745e15eee43
This commit is contained in:
303
mozilla/js/rhino/org/mozilla/javascript/DToA.java
Normal file
303
mozilla/js/rhino/org/mozilla/javascript/DToA.java
Normal file
@@ -0,0 +1,303 @@
|
||||
/* -*- Mode: java; tab-width: 8; indent-tabs-mode: nil; c-basic-offset: 4 -*-
|
||||
*
|
||||
* The contents of this file are subject to the Netscape Public
|
||||
* License Version 1.1 (the "License"); you may not use this file
|
||||
* except in compliance with the License. You may obtain a copy of
|
||||
* the License at http://www.mozilla.org/NPL/
|
||||
*
|
||||
* Software distributed under the License is distributed on an "AS
|
||||
* IS" basis, WITHOUT WARRANTY OF ANY KIND, either express oqr
|
||||
* implied. See the License for the specific language governing
|
||||
* rights and limitations under the License.
|
||||
*
|
||||
* The Original Code is Rhino code, released
|
||||
* May 6, 1999.
|
||||
*
|
||||
* The Initial Developer of the Original Code is Netscape
|
||||
* Communications Corporation. Portions created by Netscape are
|
||||
* Copyright (C) 1997-1999 Netscape Communications Corporation. All
|
||||
* Rights Reserved.
|
||||
*
|
||||
* Contributor(s):
|
||||
* Patrick Beard
|
||||
* Norris Boyd
|
||||
* Roger Lawrence
|
||||
* Frank Mitchell
|
||||
* Andrew Wason
|
||||
*
|
||||
* Alternatively, the contents of this file may be used under the
|
||||
* terms of the GNU Public License (the "GPL"), in which case the
|
||||
* provisions of the GPL are applicable instead of those above.
|
||||
* If you wish to allow use of your version of this file only
|
||||
* under the terms of the GPL and not to allow others to use your
|
||||
* version of this file under the NPL, indicate your decision by
|
||||
* deleting the provisions above and replace them with the notice
|
||||
* and other provisions required by the GPL. If you do not delete
|
||||
* the provisions above, a recipient may use your version of this
|
||||
* file under either the NPL or the GPL.
|
||||
*/
|
||||
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||||
package org.mozilla.javascript;
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import java.math.BigInteger;
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class DToA {
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/* "-0.0000...(1073 zeros after decimal point)...0001\0" is the longest string that we could produce,
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* which occurs when printing -5e-324 in binary. We could compute a better estimate of the size of
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* the output string and malloc fewer bytes depending on d and base, but why bother? */
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static final int DTOBASESTR_BUFFER_SIZE = 1078;
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static char BASEDIGIT(int digit) {
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return (char)((digit >= 10) ? 'a' - 10 + digit : '0' + digit);
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}
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static byte[] byteValue(long x)
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{
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byte result[] = new byte[8];
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for (int i = 7; i >= 0; i--) {
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result[i] = (byte)(x & 0xFF);
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x >>= 4;
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}
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return result;
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}
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static final int Frac_mask = 0xfffff;
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static final int Exp_shift = 20;
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static final int Exp_msk1 = 0x100000;
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static final int Bias = 1023;
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static final int P = 53;
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static final int Exp_shift1 = 20;
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static final int Exp_mask = 0x7ff00000;
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static final int Bndry_mask = 0xfffff;
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static final int Log2P = 1;
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|
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static int lo0bits(int y)
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{
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int k;
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int x = y;
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||||
|
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if ((x & 7) != 0) {
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if ((x & 1) != 0)
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return 0;
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if ((x & 2) != 0) {
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return 1;
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}
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return 2;
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}
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k = 0;
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if ((x & 0xffff) == 0) {
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k = 16;
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x >>>= 16;
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}
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if ((x & 0xff) == 0) {
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k += 8;
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x >>>= 8;
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}
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if ((x & 0xf) == 0) {
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k += 4;
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x >>>= 4;
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}
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if ((x & 0x3) == 0) {
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k += 2;
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x >>>= 2;
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}
|
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if ((x & 1) == 0) {
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k++;
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x >>>= 1;
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if ((x & 1) == 0)
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return 32;
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}
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return k;
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}
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|
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static void stuffBits(byte bits[], int offset, int val)
|
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{
|
||||
bits[offset] = (byte)(val >> 24);
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bits[offset + 1] = (byte)(val >> 16);
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bits[offset + 2] = (byte)(val >> 8);
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||||
bits[offset + 3] = (byte)(val);
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||||
}
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|
||||
/* converts d to bits * 2^e format */
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static int d2b(double d, byte bits[])
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{
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int e, k, y, z, de;
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long dBits = Double.doubleToLongBits(d);
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int d0 = (int)(dBits >>> 32);
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int d1 = (int)(dBits);
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z = d0 & Frac_mask;
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d0 &= 0x7fffffff; /* clear sign bit, which we ignore */
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if ((de = (int)(d0 >>> Exp_shift)) != 0)
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z |= Exp_msk1;
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|
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if ((y = d1) != 0) {
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k = lo0bits(y);
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y >>>= k;
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if (k != 0) {
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stuffBits(bits, 4, y | z << (32 - k));
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z >>= k;
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}
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else
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stuffBits(bits, 4, y);
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stuffBits(bits, 0, z);
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}
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else {
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// JS_ASSERT(z);
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k = lo0bits(z);
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z >>>= k;
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stuffBits(bits, 4, z);
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k += 32;
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||||
}
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if (de != 0) {
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e = de - Bias - (P-1) + k;
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}
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else {
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e = de - Bias - (P-1) + 1 + k;
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}
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return e;
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}
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public static String JS_dtobasestr(int base, double d)
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{
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char[] buffer; /* The output string */
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int p; /* index to current position in the buffer */
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int pInt; /* index to the beginning of the integer part of the string */
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int q;
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||||
int digit;
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double di; /* d truncated to an integer */
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double df; /* The fractional part of d */
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// JS_ASSERT(base >= 2 && base <= 36);
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buffer = new char[DTOBASESTR_BUFFER_SIZE];
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||||
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p = 0;
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if (d < 0.0) {
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buffer[p++] = '-';
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d = -d;
|
||||
}
|
||||
|
||||
/* Check for Infinity and NaN */
|
||||
if (Double.isNaN(d))
|
||||
return "NaN";
|
||||
else
|
||||
if (Double.isInfinite(d))
|
||||
return "Infinity";
|
||||
|
||||
/* Output the integer part of d with the digits in reverse order. */
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||||
pInt = p;
|
||||
di = (int)d;
|
||||
BigInteger b = new BigInteger(byteValue((long)di));
|
||||
String intDigits = b.toString(base);
|
||||
intDigits.getChars(0, intDigits.length(), buffer, p);
|
||||
p += intDigits.length();
|
||||
|
||||
df = d - di;
|
||||
if (df != 0.0) {
|
||||
/* We have a fraction. */
|
||||
|
||||
byte bits[] = new byte[8];
|
||||
|
||||
buffer[p++] = '.';
|
||||
|
||||
long dBits = Double.doubleToLongBits(d);
|
||||
int word0 = (int)(dBits >> 32);
|
||||
int word1 = (int)(dBits);
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||||
|
||||
int e = d2b(df, bits);
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||||
b = new BigInteger(bits);
|
||||
// JS_ASSERT(e < 0);
|
||||
/* At this point df = b * 2^e. e must be less than zero because 0 < df < 1. */
|
||||
|
||||
int s2 = -(word0 >>> Exp_shift1 & Exp_mask >> Exp_shift1);
|
||||
if (s2 == 0)
|
||||
s2 = -1;
|
||||
s2 += Bias + P;
|
||||
/* 1/2^s2 = (nextDouble(d) - d)/2 */
|
||||
// JS_ASSERT(-s2 < e);
|
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bits = new byte[1];
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bits[0] = 1;
|
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BigInteger mlo = new BigInteger(bits);
|
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BigInteger mhi = mlo;
|
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if ((word1 == 0) && ((word0 & Bndry_mask) == 0)
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||||
&& ((word0 & (Exp_mask & Exp_mask << 1)) != 0)) {
|
||||
/* The special case. Here we want to be within a quarter of the last input
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||||
significant digit instead of one half of it when the output string's value is less than d. */
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s2 += Log2P;
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||||
bits[0] = 1<<Log2P;
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mhi = new BigInteger(bits);
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||||
}
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||||
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b = b.shiftLeft(e + s2);
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||||
bits[0] = 1;
|
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BigInteger s = new BigInteger(bits);
|
||||
s = s.shiftLeft(s2);
|
||||
/* At this point we have the following:
|
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* s = 2^s2;
|
||||
* 1 > df = b/2^s2 > 0;
|
||||
* (d - prevDouble(d))/2 = mlo/2^s2;
|
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* (nextDouble(d) - d)/2 = mhi/2^s2. */
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||||
bits[0] = (byte)base; // s'ok since base < 36
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BigInteger bigBase = new BigInteger(bits);
|
||||
|
||||
System.out.println("s2 = " + s2 + ", e = " + e + ", b = " + b.toString());
|
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System.out.println("mhi = " + mhi.toString());
|
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System.out.println("mlo = " + mlo.toString());
|
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||||
boolean done = false;
|
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do {
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||||
b = b.multiply(bigBase);
|
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BigInteger[] divResult = b.divideAndRemainder(s);
|
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b = divResult[1];
|
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digit = (char)(divResult[0].intValue());
|
||||
if (mlo == mhi)
|
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mlo = mhi = mlo.multiply(bigBase);
|
||||
else {
|
||||
mlo = mlo.multiply(bigBase);
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||||
mhi = mhi.multiply(bigBase);
|
||||
}
|
||||
|
||||
/* Do we yet have the shortest string that will round to d? */
|
||||
int j = b.compareTo(mlo);
|
||||
/* j is b/2^s2 compared with mlo/2^s2. */
|
||||
BigInteger delta = s.subtract(mhi);
|
||||
int j1 = (delta.signum() <= 0) ? 1 : b.compareTo(delta);
|
||||
/* j1 is b/2^s2 compared with 1 - mhi/2^s2. */
|
||||
if (j1 == 0 && ((word1 & 1) == 0)) {
|
||||
if (j > 0)
|
||||
digit++;
|
||||
done = true;
|
||||
} else
|
||||
if (j < 0 || (j == 0 && ((word1 & 1) == 0))) {
|
||||
if (j1 > 0) {
|
||||
/* Either dig or dig+1 would work here as the least significant digit.
|
||||
Use whichever would produce an output value closer to d. */
|
||||
b = b.shiftLeft(1);
|
||||
j1 = b.compareTo(s);
|
||||
if (j1 > 0) /* The even test (|| (j1 == 0 && (digit & 1))) is not here because it messes up odd base output
|
||||
* such as 3.5 in base 3. */
|
||||
digit++;
|
||||
}
|
||||
done = true;
|
||||
} else if (j1 > 0) {
|
||||
digit++;
|
||||
done = true;
|
||||
}
|
||||
// JS_ASSERT(digit < (uint32)base);
|
||||
buffer[p++] = BASEDIGIT(digit);
|
||||
} while (!done);
|
||||
}
|
||||
|
||||
return new String(buffer, 0, p);
|
||||
}
|
||||
|
||||
}
|
||||
|
||||
@@ -437,11 +437,7 @@ public class ScriptRuntime {
|
||||
}
|
||||
|
||||
if (base != 10) {
|
||||
/* Monkey see, Rhino do */
|
||||
if (d < 0)
|
||||
return "-" + Long.toString( ((long)-d) & 0xFFFFFFFFL, base);
|
||||
else
|
||||
return Long.toString( ((long)d) & 0xFFFFFFFFL, base);
|
||||
return DToA.JS_dtobasestr(base, d);
|
||||
}
|
||||
else {
|
||||
// Okay, this is gross. But Java doesn't seem to have any number
|
||||
@@ -2136,6 +2132,7 @@ public class ScriptRuntime {
|
||||
}
|
||||
|
||||
static boolean hasProp(Scriptable start, String name) {
|
||||
|
||||
Scriptable m = start;
|
||||
do {
|
||||
if (m.has(name, start))
|
||||
|
||||
303
mozilla/js/rhino/src/org/mozilla/javascript/DToA.java
Normal file
303
mozilla/js/rhino/src/org/mozilla/javascript/DToA.java
Normal file
@@ -0,0 +1,303 @@
|
||||
/* -*- Mode: java; tab-width: 8; indent-tabs-mode: nil; c-basic-offset: 4 -*-
|
||||
*
|
||||
* The contents of this file are subject to the Netscape Public
|
||||
* License Version 1.1 (the "License"); you may not use this file
|
||||
* except in compliance with the License. You may obtain a copy of
|
||||
* the License at http://www.mozilla.org/NPL/
|
||||
*
|
||||
* Software distributed under the License is distributed on an "AS
|
||||
* IS" basis, WITHOUT WARRANTY OF ANY KIND, either express oqr
|
||||
* implied. See the License for the specific language governing
|
||||
* rights and limitations under the License.
|
||||
*
|
||||
* The Original Code is Rhino code, released
|
||||
* May 6, 1999.
|
||||
*
|
||||
* The Initial Developer of the Original Code is Netscape
|
||||
* Communications Corporation. Portions created by Netscape are
|
||||
* Copyright (C) 1997-1999 Netscape Communications Corporation. All
|
||||
* Rights Reserved.
|
||||
*
|
||||
* Contributor(s):
|
||||
* Patrick Beard
|
||||
* Norris Boyd
|
||||
* Roger Lawrence
|
||||
* Frank Mitchell
|
||||
* Andrew Wason
|
||||
*
|
||||
* Alternatively, the contents of this file may be used under the
|
||||
* terms of the GNU Public License (the "GPL"), in which case the
|
||||
* provisions of the GPL are applicable instead of those above.
|
||||
* If you wish to allow use of your version of this file only
|
||||
* under the terms of the GPL and not to allow others to use your
|
||||
* version of this file under the NPL, indicate your decision by
|
||||
* deleting the provisions above and replace them with the notice
|
||||
* and other provisions required by the GPL. If you do not delete
|
||||
* the provisions above, a recipient may use your version of this
|
||||
* file under either the NPL or the GPL.
|
||||
*/
|
||||
|
||||
package org.mozilla.javascript;
|
||||
|
||||
import java.math.BigInteger;
|
||||
|
||||
class DToA {
|
||||
|
||||
|
||||
/* "-0.0000...(1073 zeros after decimal point)...0001\0" is the longest string that we could produce,
|
||||
* which occurs when printing -5e-324 in binary. We could compute a better estimate of the size of
|
||||
* the output string and malloc fewer bytes depending on d and base, but why bother? */
|
||||
|
||||
static final int DTOBASESTR_BUFFER_SIZE = 1078;
|
||||
|
||||
static char BASEDIGIT(int digit) {
|
||||
return (char)((digit >= 10) ? 'a' - 10 + digit : '0' + digit);
|
||||
}
|
||||
|
||||
static byte[] byteValue(long x)
|
||||
{
|
||||
byte result[] = new byte[8];
|
||||
for (int i = 7; i >= 0; i--) {
|
||||
result[i] = (byte)(x & 0xFF);
|
||||
x >>= 4;
|
||||
}
|
||||
return result;
|
||||
}
|
||||
|
||||
static final int Frac_mask = 0xfffff;
|
||||
static final int Exp_shift = 20;
|
||||
static final int Exp_msk1 = 0x100000;
|
||||
static final int Bias = 1023;
|
||||
static final int P = 53;
|
||||
|
||||
static final int Exp_shift1 = 20;
|
||||
static final int Exp_mask = 0x7ff00000;
|
||||
static final int Bndry_mask = 0xfffff;
|
||||
static final int Log2P = 1;
|
||||
|
||||
|
||||
static int lo0bits(int y)
|
||||
{
|
||||
int k;
|
||||
int x = y;
|
||||
|
||||
if ((x & 7) != 0) {
|
||||
if ((x & 1) != 0)
|
||||
return 0;
|
||||
if ((x & 2) != 0) {
|
||||
return 1;
|
||||
}
|
||||
return 2;
|
||||
}
|
||||
k = 0;
|
||||
if ((x & 0xffff) == 0) {
|
||||
k = 16;
|
||||
x >>>= 16;
|
||||
}
|
||||
if ((x & 0xff) == 0) {
|
||||
k += 8;
|
||||
x >>>= 8;
|
||||
}
|
||||
if ((x & 0xf) == 0) {
|
||||
k += 4;
|
||||
x >>>= 4;
|
||||
}
|
||||
if ((x & 0x3) == 0) {
|
||||
k += 2;
|
||||
x >>>= 2;
|
||||
}
|
||||
if ((x & 1) == 0) {
|
||||
k++;
|
||||
x >>>= 1;
|
||||
if ((x & 1) == 0)
|
||||
return 32;
|
||||
}
|
||||
return k;
|
||||
}
|
||||
|
||||
static void stuffBits(byte bits[], int offset, int val)
|
||||
{
|
||||
bits[offset] = (byte)(val >> 24);
|
||||
bits[offset + 1] = (byte)(val >> 16);
|
||||
bits[offset + 2] = (byte)(val >> 8);
|
||||
bits[offset + 3] = (byte)(val);
|
||||
}
|
||||
|
||||
/* converts d to bits * 2^e format */
|
||||
static int d2b(double d, byte bits[])
|
||||
{
|
||||
int e, k, y, z, de;
|
||||
long dBits = Double.doubleToLongBits(d);
|
||||
int d0 = (int)(dBits >>> 32);
|
||||
int d1 = (int)(dBits);
|
||||
|
||||
z = d0 & Frac_mask;
|
||||
d0 &= 0x7fffffff; /* clear sign bit, which we ignore */
|
||||
|
||||
if ((de = (int)(d0 >>> Exp_shift)) != 0)
|
||||
z |= Exp_msk1;
|
||||
|
||||
if ((y = d1) != 0) {
|
||||
k = lo0bits(y);
|
||||
y >>>= k;
|
||||
if (k != 0) {
|
||||
stuffBits(bits, 4, y | z << (32 - k));
|
||||
z >>= k;
|
||||
}
|
||||
else
|
||||
stuffBits(bits, 4, y);
|
||||
stuffBits(bits, 0, z);
|
||||
}
|
||||
else {
|
||||
// JS_ASSERT(z);
|
||||
k = lo0bits(z);
|
||||
z >>>= k;
|
||||
stuffBits(bits, 4, z);
|
||||
k += 32;
|
||||
}
|
||||
if (de != 0) {
|
||||
e = de - Bias - (P-1) + k;
|
||||
}
|
||||
else {
|
||||
e = de - Bias - (P-1) + 1 + k;
|
||||
}
|
||||
return e;
|
||||
}
|
||||
|
||||
public static String JS_dtobasestr(int base, double d)
|
||||
{
|
||||
char[] buffer; /* The output string */
|
||||
int p; /* index to current position in the buffer */
|
||||
int pInt; /* index to the beginning of the integer part of the string */
|
||||
|
||||
int q;
|
||||
int digit;
|
||||
double di; /* d truncated to an integer */
|
||||
double df; /* The fractional part of d */
|
||||
|
||||
// JS_ASSERT(base >= 2 && base <= 36);
|
||||
|
||||
buffer = new char[DTOBASESTR_BUFFER_SIZE];
|
||||
|
||||
p = 0;
|
||||
if (d < 0.0) {
|
||||
buffer[p++] = '-';
|
||||
d = -d;
|
||||
}
|
||||
|
||||
/* Check for Infinity and NaN */
|
||||
if (Double.isNaN(d))
|
||||
return "NaN";
|
||||
else
|
||||
if (Double.isInfinite(d))
|
||||
return "Infinity";
|
||||
|
||||
/* Output the integer part of d with the digits in reverse order. */
|
||||
pInt = p;
|
||||
di = (int)d;
|
||||
BigInteger b = new BigInteger(byteValue((long)di));
|
||||
String intDigits = b.toString(base);
|
||||
intDigits.getChars(0, intDigits.length(), buffer, p);
|
||||
p += intDigits.length();
|
||||
|
||||
df = d - di;
|
||||
if (df != 0.0) {
|
||||
/* We have a fraction. */
|
||||
|
||||
byte bits[] = new byte[8];
|
||||
|
||||
buffer[p++] = '.';
|
||||
|
||||
long dBits = Double.doubleToLongBits(d);
|
||||
int word0 = (int)(dBits >> 32);
|
||||
int word1 = (int)(dBits);
|
||||
|
||||
int e = d2b(df, bits);
|
||||
b = new BigInteger(bits);
|
||||
// JS_ASSERT(e < 0);
|
||||
/* At this point df = b * 2^e. e must be less than zero because 0 < df < 1. */
|
||||
|
||||
int s2 = -(word0 >>> Exp_shift1 & Exp_mask >> Exp_shift1);
|
||||
if (s2 == 0)
|
||||
s2 = -1;
|
||||
s2 += Bias + P;
|
||||
/* 1/2^s2 = (nextDouble(d) - d)/2 */
|
||||
// JS_ASSERT(-s2 < e);
|
||||
bits = new byte[1];
|
||||
bits[0] = 1;
|
||||
BigInteger mlo = new BigInteger(bits);
|
||||
BigInteger mhi = mlo;
|
||||
if ((word1 == 0) && ((word0 & Bndry_mask) == 0)
|
||||
&& ((word0 & (Exp_mask & Exp_mask << 1)) != 0)) {
|
||||
/* The special case. Here we want to be within a quarter of the last input
|
||||
significant digit instead of one half of it when the output string's value is less than d. */
|
||||
s2 += Log2P;
|
||||
bits[0] = 1<<Log2P;
|
||||
mhi = new BigInteger(bits);
|
||||
}
|
||||
|
||||
b = b.shiftLeft(e + s2);
|
||||
bits[0] = 1;
|
||||
BigInteger s = new BigInteger(bits);
|
||||
s = s.shiftLeft(s2);
|
||||
/* At this point we have the following:
|
||||
* s = 2^s2;
|
||||
* 1 > df = b/2^s2 > 0;
|
||||
* (d - prevDouble(d))/2 = mlo/2^s2;
|
||||
* (nextDouble(d) - d)/2 = mhi/2^s2. */
|
||||
bits[0] = (byte)base; // s'ok since base < 36
|
||||
BigInteger bigBase = new BigInteger(bits);
|
||||
|
||||
System.out.println("s2 = " + s2 + ", e = " + e + ", b = " + b.toString());
|
||||
System.out.println("mhi = " + mhi.toString());
|
||||
System.out.println("mlo = " + mlo.toString());
|
||||
|
||||
boolean done = false;
|
||||
do {
|
||||
b = b.multiply(bigBase);
|
||||
BigInteger[] divResult = b.divideAndRemainder(s);
|
||||
b = divResult[1];
|
||||
digit = (char)(divResult[0].intValue());
|
||||
if (mlo == mhi)
|
||||
mlo = mhi = mlo.multiply(bigBase);
|
||||
else {
|
||||
mlo = mlo.multiply(bigBase);
|
||||
mhi = mhi.multiply(bigBase);
|
||||
}
|
||||
|
||||
/* Do we yet have the shortest string that will round to d? */
|
||||
int j = b.compareTo(mlo);
|
||||
/* j is b/2^s2 compared with mlo/2^s2. */
|
||||
BigInteger delta = s.subtract(mhi);
|
||||
int j1 = (delta.signum() <= 0) ? 1 : b.compareTo(delta);
|
||||
/* j1 is b/2^s2 compared with 1 - mhi/2^s2. */
|
||||
if (j1 == 0 && ((word1 & 1) == 0)) {
|
||||
if (j > 0)
|
||||
digit++;
|
||||
done = true;
|
||||
} else
|
||||
if (j < 0 || (j == 0 && ((word1 & 1) == 0))) {
|
||||
if (j1 > 0) {
|
||||
/* Either dig or dig+1 would work here as the least significant digit.
|
||||
Use whichever would produce an output value closer to d. */
|
||||
b = b.shiftLeft(1);
|
||||
j1 = b.compareTo(s);
|
||||
if (j1 > 0) /* The even test (|| (j1 == 0 && (digit & 1))) is not here because it messes up odd base output
|
||||
* such as 3.5 in base 3. */
|
||||
digit++;
|
||||
}
|
||||
done = true;
|
||||
} else if (j1 > 0) {
|
||||
digit++;
|
||||
done = true;
|
||||
}
|
||||
// JS_ASSERT(digit < (uint32)base);
|
||||
buffer[p++] = BASEDIGIT(digit);
|
||||
} while (!done);
|
||||
}
|
||||
|
||||
return new String(buffer, 0, p);
|
||||
}
|
||||
|
||||
}
|
||||
|
||||
@@ -437,11 +437,7 @@ public class ScriptRuntime {
|
||||
}
|
||||
|
||||
if (base != 10) {
|
||||
/* Monkey see, Rhino do */
|
||||
if (d < 0)
|
||||
return "-" + Long.toString( ((long)-d) & 0xFFFFFFFFL, base);
|
||||
else
|
||||
return Long.toString( ((long)d) & 0xFFFFFFFFL, base);
|
||||
return DToA.JS_dtobasestr(base, d);
|
||||
}
|
||||
else {
|
||||
// Okay, this is gross. But Java doesn't seem to have any number
|
||||
@@ -2136,6 +2132,7 @@ public class ScriptRuntime {
|
||||
}
|
||||
|
||||
static boolean hasProp(Scriptable start, String name) {
|
||||
|
||||
Scriptable m = start;
|
||||
do {
|
||||
if (m.has(name, start))
|
||||
|
||||
Reference in New Issue
Block a user