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Bug 399028: Do not display all pending requests by default when the user is logged out - Patch by Frédéric Buclin <LpSolit@gmail.com> a=LpSolit

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git-svn-id: svn://10.0.0.236/trunk@237449 18797224-902f-48f8-a5cc-f745e15eee43
This commit is contained in:
lpsolit%gmail.com
2007-10-09 10:45:01 +00:00
parent ad8684c0fd
commit 99b4687996
1 changed files with 11 additions and 4 deletions
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15
mozilla/webtools/bugzilla/request.cgi
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@@ -42,6 +42,10 @@ use Bugzilla::Component;
# Make sure the user is logged in.
my $user = Bugzilla->login();
my $cgi = Bugzilla->cgi;
my $template = Bugzilla->template;
my $action = $cgi->param('action') || '';
print $cgi->header();
################################################################################
# Main Body Execution
@@ -59,7 +63,13 @@ unless (defined $cgi->param('requestee')
Bugzilla::User::match_field($cgi, $fields);
queue();
if ($action eq 'queue') {
queue();
}
else {
$template->process('request/queue.html.tmpl', {requests => {}})
|| ThrowTemplateError($template->error());
}
exit;
################################################################################
@@ -288,9 +298,6 @@ sub queue {
$vars->{'requests'} = \@requests;
$vars->{'types'} = \@types;
# Return the appropriate HTTP response headers.
print $cgi->header();
# Generate and return the UI (HTML page) from the appropriate template.
$template->process("request/queue.html.tmpl", $vars)
|| ThrowTemplateError($template->error());